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x^2-2x=x-10
We move all terms to the left:
x^2-2x-(x-10)=0
We get rid of parentheses
x^2-2x-x+10=0
We add all the numbers together, and all the variables
x^2-3x+10=0
a = 1; b = -3; c = +10;
Δ = b2-4ac
Δ = -32-4·1·10
Δ = -31
Delta is less than zero, so there is no solution for the equation
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